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	<title>Comments on: How do you find the orbital radius of a satellite (GPS)  if you are only given the speed at which it orbits?</title>
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	<link>http://www.foxfire1.com/speed-gps/how-do-you-find-the-orbital-radius-of-a-satellite-gps-if-you-are-only-given-the-speed-at-which-it-orbits</link>
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		<title>By: Alexey V</title>
		<link>http://www.foxfire1.com/speed-gps/how-do-you-find-the-orbital-radius-of-a-satellite-gps-if-you-are-only-given-the-speed-at-which-it-orbits/comment-page-1#comment-1475</link>
		<dc:creator>Alexey V</dc:creator>
		<pubDate>Mon, 08 Mar 2010 02:31:59 +0000</pubDate>
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		<description>To be on an orbit of radius R the satellite shoud experience centripetal acceleration V^2/R. This acceleration is provided by gravity force and equal GM/R^2. On the Earth surface this acceleration is g = 9.8 m/s^2, so GM/r^2 = g, where r=6.4*10^6 m is Earth radius. Then GM = gr^2 and acceleration on distance R is gr^2/R^2 and equal to V^2/R. Now we have an equation:
gr^2/R^2 = V^2/R. Solve over R and get R = gr^2/V^2.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>To be on an orbit of radius R the satellite shoud experience centripetal acceleration V^2/R. This acceleration is provided by gravity force and equal GM/R^2. On the Earth surface this acceleration is g = 9.8 m/s^2, so GM/r^2 = g, where r=6.4*10^6 m is Earth radius. Then GM = gr^2 and acceleration on distance R is gr^2/R^2 and equal to V^2/R. Now we have an equation:<br />
gr^2/R^2 = V^2/R. Solve over R and get R = gr^2/V^2.<br /><b>References : </b></p>
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